How do you find the limit of #(x+3)^2007# as #x->-oo#?

Question

How do you find the limit of #(x+3)^2007# as #x->-oo#?

1 Answer

Impact of this question

1435 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-08T05:55:45

#-∞#

Explanation:

Without using the concept of limits, -#∞+3# should still be #-∞#. And since the number 2007 is an odd number, the answer should still be -#∞#. So, you could say that the answer diverges towards negative infinity.

Science

Math

Humanities

... and beyond

How do you find the limit of #(x+3)^2007# as #x->-oo#?

1 Answer

Explanation:

Related questions

Impact of this question