How do you find the limit of #(x+3)^2007# as #x->-oo#?

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How do you find the limit of #(x+3)^2007# as #x->-oo#?

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Answer 1 · 2018-02-08T05:55:45

#-∞#

Explanation:

Without using the concept of limits, -#∞+3# should still be #-∞#. And since the number 2007 is an odd number, the answer should still be -#∞#. So, you could say that the answer diverges towards negative infinity.

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How do you find the limit of #(x+3)^2007# as #x->-oo#?

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