How do you find the limit of #(x^2+x-6)/(x+3) as x approaches -3?
1 Answer
Jul 27, 2015
With quadratic terms, you factorise.
Explanation:
As long as
The limit for
graph{(x^2+x-6)/(x+3) [-9.5, 10.5, -7.32, 2.68]}
