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How do you find the limit of #(t^2+t-2)/(t^2-1)# as #t->1#?

1 Answer

Feb 17, 2017

#3/2#

Explanation:

Factorisation first,

#((t+2)(t-1))/((t-1)(t+1))#. # (t-1)#gets cancelled out. Thus it is,

#lim_(t->1) (t+2)/(t+1)#

=#3/2#

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