How do you find the limit of #sin^2x/(1-cosx)# as #x->0#?
1 Answer
Nov 3, 2016
One method is shown below.
Explanation:
Use algebra, trigonometry and the continuity of
# = lim_(xrarr0)((1-cosx)(1+cosx))/(1-cosx)#
# = lim_(xrarr0)(1+cosx)#
# = 1+cos(0) = 1 + 1 =2#
