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How do you find the limit of #R(x) = (x - 1)/(x² - 1)# as x approaches #-1#?

1 Answer

Nov 2, 2016

You need to manipulate the denominator and simplify before evaluating the limit

Explanation:

Using that #x^2-1 = (x+1) (x-1)#, we can write:

#R(x)= (x-1)/((x+1) (x-1))# we can then simplify and we have:

#R(x)=1/(x+1)#, so we have:

#lim_(xrarr-1) R(x)=lim_(xrarr-1) 1/(x+1)=oo#

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