How do you find the Limit of $ln [\frac{R - 3}{R - 2}]$ $ln[(R-3)/(R-2)]$ as R approaches infinity?

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Answer 1 · 2017-01-06T19:55:39

$lim_(R->oo) ln((R-3)/(R-2)) =0$

Dividing numerator and denominator of the rational function by $R$ you have:

$lim_(R->oo) ln((R-3)/(R-2)) = lim_(R->oo) ln((1-3/R)/(1-2/R))=ln1 = 0$

How do you find the Limit of ln[(R-3)/(R-2)] ln[R−3R−2]ln[(R-3)/(R-2)] as R approaches infinity?