How do you find the limit of #(4x^2 -3x+2)/(7x^2 +2x-1)# as x approaches infinity?
1 Answer
Feb 16, 2016
Explanation:
divide numerator and denominator by the highest exponent of x , in this case
# x^2# hence
#( (4x^2)/x^2 - (3x)/x^2 + 2/x^2)/((7x^2)/x^2 + (2x)/x^2 - 1/x^2) #
#= (4 - 3/x +2/x^2)/(7 + 2/x -1/x^2) #
#rArr lim_(x→∞) f(x) = 4/7 # graph{(4x^2-3x+2)/(7x^2+2x-1) [-5.07, 5.067, -2.526, 2.54]}
