How do you find the limit of #(4^y) / (y^2)# as y approaches 0?

1 Answer
SCooke
Sep 7, 2017

#lim_(y->0) (4^y)/y^2 = +oo#

Explanation:

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples. (From: https://socratic.org/calculus/limits/determining-limits-algebraically) Many more details, and a good video there too.

In this case the controlling factor is the denominator. No matter what path the numerator takes, the ratio must approach #+oo# as #y -> 0#

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