How do you find the limit of #2x+5# as #x->-oo#?
1 Answer
Dec 30, 2016
#lim_(x rarr -oo) (2x+5)# does not exist
Explanation:
As
# x rarr -oo => 3x rarr -oo #
# " " => 2x+5 rarr -oo #
Hence:
# 2x+5 # is unbounded as#x rarr -oo #
And so,
#lim_(x rarr -oo) (2x+5)# does not exist
