How do you find the limit of # (1)/(x-2)# as x approaches #2^+#?
1 Answer
Apr 28, 2016
Explanation:
Given,
#lim_(xrarr2^+)1/(x-2)#
Substitute
#=lim_(xrarr2^+)1/((2^+)-2#
#=lim_(xrarr2^+)1/0^+#
#=infty#
