How do you find the limit #lim_(x->2^-)1/(x-2)#?
1 Answer
Oct 12, 2017
negative infinity
Explanation:
as x goes to 2 from below - so imagine a number just a tiny bit LESS than 2.
This number minus 2 gives a remainder that is a very tiny negative number.
1 divided by a negative number is negative, and one divided by a tiny negative number is a very large negative number.
So you can say that the function tends to negative infinity as x approaches 2 from below. (or from the left)
It's often good to have a graph of the function as a sanity check...
graph{1/(x-2) [-10, 10, -5, 5]}
