How do you find the limit of # [(1/t)-(1/t^2+t)]# as t approaches 0?
1 Answer
Mar 4, 2016
Explanation:
#= lim_{t -> 0}((-t^3 + t - 1)/t^2)#
#= lim_{t -> 0}((-(0)^3 + (0) - 1)/t^2)#
#= lim_{t -> 0}((- 1)/t^2)#
#= -oo#
graph{1/x - 1/x^2 -x [-10, 10, -5, 5]}
