How do you find the limit #ln(x^2+1)/x# as #x->0#?
2 Answers
Limit as x->0 of
Explanation:
Direct application give
So we use l'Hôpital rule
l'Hopital's Rule applies.
Explanation:
If we try to evaluate at the limit we obtain:
This means that l'Hopital's Rule applies.
To apply l'Hopital's Rule, you, compute the derivative of numerator, compute the derivative of the denominator, and then reassemble the two derivatives into a new fraction.
The derivative of the numerator:
The derivative of the denominator:
Here is our new expression:
l'Hopital's Rule states that the limit of our new expression goes to the limit as the original expression
