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How do you find the inverse of the function #y=log(x-2)#?

1 Answer

Nov 19, 2016

#f^-1(x) = 10^x + 2#

Explanation:

Switch the #x# and #y# values and solve for #y#.

#y = log(x- 2)#

#x = log(y - 2)#

#10^x = y- 2#

#y = 10^x + 2#

Hopefully this helps!

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