How do you find the intercepts for $y = 7 x + 3$ $y= 7x + 3$ ?

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How do you find the intercepts for $y = 7 x + 3$ $y= 7x + 3$ ?

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Answer 1 · 2018-05-20T19:01:20

x: ( $- \frac{3}{7}, 0$ $-3/7,0$ )
y: ( $0, 3$ $0,3$ )

Explanation:

x-intercept: set y=0
$0 = 7 x + 3$ $\color(red)(0)=7x+3$
$- 3 = 7 x$ $-3=7x$
$- \frac{3}{7} = x$ $-3/7=x$

y-intercept: set x=0
$y = 7 (0) + 3$ $y=7(\color(red)(0))+3$
$y = 0 + 3 = 3$ $y=0+3=3$

Alternatively, you can already find the y-intercept because it is in the setup of the equation.
$y = m x + b$ $y=mx+b$ where $m = slope = 7$ $m=\text(slope)=7$ and
$b = y-intercept = 3$ $b=\text(y-intercept)=3$ .

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How do you find the intercepts for $y = 7 x + 3$ $y= 7x + 3$ ?

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How do you find the intercepts for $y = 7 x + 3$ $y= 7x + 3$ ?