How do you find the intercepts for $5 x + y = 20$ $5x+y=20$ ?

Question

5135 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-01T00:40:01

$x -$ $x-$ intercept: $(4, 0)$ $(4,0)$ $y -$ $y-$ intercept: $(0, 20)$ $(0,20)$

To determine the $x -$ $x-$ intercept, set $y = 0$ $y=0$ in the equation and solve:

$5 x + 0 = 20$ $5x+0=20$

$x = \frac{20}{5} = 4$ $x=20/5=4$

The $x -$ $x-$ intercept is $(4, 0)$ $(4, 0)$ .

To determine the $y -$ $y-$ intercept, set $x = 0$ $x=0$ in the equation and solve:

$5 (0) + y = 20$ $5(0)+y=20$

$y = 20$ $y=20$

The $y -$ $y-$ intercept is $(0, 20) .$ $(0,20).$

How do you find the intercepts for 5x+y=205x+y=205x+y=20?