How do you find the intercepts for #5x+y=20#?

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Answer 1 · 2018-04-01T00:40:01

#x-#intercept: #(4,0)# #y-#intercept: #(0,20)#

To determine the #x-#intercept, set #y=0# in the equation and solve:

#5x+0=20#

#x=20/5=4#

The #x-#intercept is #(4, 0)#.

To determine the #y-#intercept, set #x=0# in the equation and solve:

#5(0)+y=20#

#y=20#

The #y-#intercept is #(0,20).#