How do you find the intercepts for $4x+3y=8$ ?

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Answer 1 · 2018-03-25T12:33:32

$x$ -intercept $(2,0)$
$y$ -intercept $(0,8/3)$

To find the $x$ -intercept, substitute $y=0$ ,

$4x=8$
$x=2$

To find the $y$ -intercept, substitute $x=0$ ,

$3y=8$
$y=8/3$

Hence, the $x$ -intercepts and $y$ -intercepts are $(2,0)$ and $(0,8/3)$ respectively.

Answer 2 · 2018-03-25T12:42:11

The graph intersects the $X$ axis in $P_1(2,0)$ and the $Y$ axis in $P_2(0,8/3)$ .

The graph intersects the $Y$ axis when $X=0$ and the $X$ axis when $Y=0$ . Therefore, taking $4x+3y=8$ and the cases:

graph{4x+3y=8 [-7.024, 7.02, -3.51, 3.51]}

How do you find the intercepts for 4x+3y=84x+3y=8?