How do you find the intercepts for 3x + 4y = -4?

2 Answers
Jim G.
Jun 16, 2018

"x-intercept "=-4/3," y-intercept "=-1

Explanation:

"to find the intercepts, that is where the graph crosses"
"the x and y axes"

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

x=0rArr0+4y=-4rArry=-1larrcolor(red)"y-intercept"

y=0rArr3x+0=-4rArrx=-4/3larrcolor(red)"x-intercept"
graph{(y+3/4x+1)((x-0)^2+(y+1)^2-0.04)((x+4/3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

Kalyanam S.
Jun 16, 2018

x / -(4/3) + y/-1 = 1 is the intercept form of the line.

x-intercept = (4/3), y-intercept = -1

Explanation:

Intercept form of equation is x/a + y/b = 1

3x + 4y = -4

-(3/4)x - cancel(4/4)y = 1

x / -(4/3) + y/-1 =1

x-intercept = -(4/3), y-intercept = -1

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