How do you find the intercepts for $2x+y=6$ ?

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Answer 1 · 2016-11-06T00:31:55

The $x$ intercept is $(3,0)$ and the $y$ intercept is $(0, 6)$ .

$2color(blue)x+color(red)y=6$

The $x$ intercept is the point where the line crosses the $x$ axis.
$y=0$ everywhere on the $x$ axis.

To find the $x$ intercept, substitute $color(red)y=color(red)0$ into the equation and solve for $color(blue)x$ .

$2color(blue)x+color(red)0=6$

$2color(blue)x=6$

$(2color(blue)x)/2 =6/2color(white)(aaa)$ Divide both sides by 2

$color(blue)x=3$

The $x$ intercept is then $(3,0)$ .

The $y$ intercept is the point where the line crosses the $y$ axis.
$x=0$ everywhere on the $y$ axis.

To find the $y$ intercept, substitute $color(blue)x =color(blue)0$ into the equation and solve for $color(red)y$ .

$2(color(blue)0)+color(red)y=6$

$color(red)y=6$ .

The $y$ intercept is then $(0,6)$ .

How do you find the intercepts for 2x+y=62x+y=6?