How do you find the intercepts and graph the equation by plotting points y= -2?

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Answer 1 · 2016-02-09T10:33:50

Slope is $0$ $0$ and intercept is $- 2$ $-2$ .

The equation $y = - 2$ $y=-2$ is represented by a horizontal line parallel to $x$ $x$ axis as on this line $y$ $y$ is always $- 2$ $-2$ ..

As it parallel to $x$ $x$ axis, its Slope is zero.

Further, it obviously intersects $x$ $x$ axis at $y = - 2$ $y=-2$ and hence intercept is $- 2$ $-2$ .

So the equation is

$y = m \cdot x + c$ $y=m*x+c$ , where $m$ $m$ is slope and $c$ $c$ is intercept and equation becomes

$y = 0 \cdot x - 2$ $y=0*x-2$ (as slope is 0 and intercept is $- 2$ $-2$ , i.e.

$y = - 2$ $y=-2$ .

Converting $y = - 2$ $y=-2$ in the form $y = m \cdot x + c$ $y=m*x+c$ will also give

Slope as $0$ $0$ and intercept is $- 2$ $-2$ .