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How do you find the integral of #sec(3x)sec(3x)#?

1 Answer

Harish Chandra Rajpoot

Jul 23, 2018

#1/3\tan(3x)+C#

Explanation:

Given that

#\int \sec(3x)\sec(3x)\ dx#

#=\int \sec^2(3x)\ dx#

#=1/3\int \sec^2(3x)\3 dx#

#=1/3\int \sec^2(3x)\d(3x)#

#=1/3\tan(3x)+C#

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