How do you find the integral of $e^(-x)dx$ ?

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Answer 1 · 2018-05-15T07:29:04

it's $-e^(-x) + c$

let $u = -x$ then $(du)/dx = -1$ which means $dx = -du$
then
$int (e^(-x))dx = int (-e^u)du = -int (e^u)du = -e^u + c= -e^(-x) + c$

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