Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find the integral of #e^(-x)dx#?

1 Answer

May 15, 2018

it's #-e^(-x) + c#

Explanation:

let #u = -x# then #(du)/dx = -1# which means #dx = -du#
then
#int (e^(-x))dx = int (-e^u)du = -int (e^u)du = -e^u + c= -e^(-x) + c#

Related questions

See all questions in Integrals of Exponential Functions

Impact of this question

242412 views around the world

You can reuse this answer
Creative Commons License