How do you find the integral of $e^((-1/2)*x)$ ?

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Answer 1 · 2015-09-26T15:05:10

$-2e^(-1/2x)+C$

$t=-1/2x => dt=-1/2dx => dx=-2dt$

$I=int e^(-1/2x)dx = int e^t*(-2dt) = -2 inte^tdt = -2e^t + C$

$I=-2e^(-1/2x)+C$

How do you find the integral of e^((-1/2)*x)e^((-1/2)*x)?