How do you find the instantaneous rate of change of the function $y= x^2-4x$ when x=1?

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Answer 1 · 2016-05-10T14:21:06

When $x=1$ , $dy/dx = -2$

The 'instantaneous rate of change' is the same as the slope or gradient of the function and is found by calculating $dy/dx$ .

$y=x^2-4x$

$dy/dx = 2x-4$

When $x=1$ , $dy/dx = -2$

How do you find the instantaneous rate of change of the function y= x^2-4xy= x^2-4x when x=1?