How do you find the instantaneous rate of change of the function $x^2 + 3x - 4$ when x=2?

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Answer 1 · 2016-05-23T09:10:28

The instantaneous rate of change of the function $= 7$

Given -

$y=x^2+3x-4$

The first derivative of the function gives the rate of change for any value of $x$

$dy/dx=2x+3$

At $x=2$ the rate of change is -

At $x=2; dy/dx=2(2)+3=4+3=7$

How do you find the instantaneous rate of change of the function x^2 + 3x - 4x^2 + 3x - 4 when x=2?