How do you find the instantaneous rate of change of the function $f(x) = x^2 + 3x + 4$ when $x=2$ ?

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Answer 1 · 2015-03-27T20:32:42

Have you learned differentiation formulas yet, or do you need to do this using the definition?

Using differentiation formulas, find $f"(x)$ and the evaluate at $x=2$

$f'(x)=2x+3$ ,

so the instantaneous rate of change when $x=2$ is $f'(2)=2(2)+3=7$

How do you find the instantaneous rate of change of the function f(x) = x^2 + 3x + 4f(x) = x^2 + 3x + 4 when x=2x=2?