How do you find the instantaneous rate of change of the function $F(x) = e^x$ when x=0?

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Answer 1 · 2016-02-28T10:40:48

The instantaneous rate of change at $x=0$ equals with numerical value of the first derivative at $x=0$

Hence $[(d(f(x)))/dx]_(x=0)=[e^x]_(x=0)=e^0=1$

How do you find the instantaneous rate of change of the function F(x) = e^xF(x) = e^x when x=0?