How do you find the instantaneous rate of change of the function $f(x)= 3/(x-5)$ when x=1?

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Answer 1 · 2017-06-01T06:27:40

The instantaneous rate of change is $=-3/16$

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We need

$(1/x)'=-1/x^2$

Here, we have

$f(x)=3/(x-5)$

$f'(x)=-3*1/(x-5)^2$

$f'(1)=-3/(1-5)^2=-3/16$

How do you find the instantaneous rate of change of the function f(x)= 3/(x-5)f(x)= 3/(x-5) when x=1?