How do you find the instantaneous rate of change of the function $d = 200 t \cdot 2^{- t}$ $d=200t * 2^(-t)$ when t=1?

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Answer 1 · 2016-01-21T23:32:33

I found: $30.7$ $30.7$

We need to evaluate the derivative with respect to $t$ $t$ and evaluate it at $t = 1$ $t=1$ :

$d'(t)=200/2^t-200t*ln(2)/2^t=200/2^t[1-tln(2)]$

Evaluate it at $t=1$

$d'(1)=200/2^1[1-1*ln(2)]=30.7$

How do you find the instantaneous rate of change of the function d=200t * 2^(-t)d=200t⋅2−td=200t * 2^(-t) when t=1?