How do you find the instantaneous rate of change of revenue when 1000 units are produced if the revenue (in thousands of dollars) from producing x units of an item is $R(x) = 12x - .005x^2$ ?

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Answer 1 · 2015-05-10T21:26:56

Just take the derivative of $R$ and plug in $x=1000$ . Doing so gives $R'(x)=12-0.01x$ so that $R'(1000)=12-10=2$ thousand dollars per unit produced.

How do you find the instantaneous rate of change of revenue when 1000 units are produced if the revenue (in thousands of dollars) from producing x units of an item is R(x) = 12x - .005x^2R(x) = 12x - .005x^2?