How do you find the instantaneous rate of change for the volume of a growing spherical cell given by $v = (4/3) (pi) r^3$ when r is 5?

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How do you find the instantaneous rate of change for the volume of a growing spherical cell given by $v = (4/3) (pi) r^3$ when r is 5?

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Answer 1 · 2015-03-27T22:27:46

Firs evaluate the derivative of your volume (with respect to $r$ :
$V'(r)=(dV(r))/(dr)=(4/3)pi*3r^2$
Now substitute $r=5$ in it:
$V'(5)=(4/3)pi*3*25=100pi$

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How do you find the instantaneous rate of change for the volume of a growing spherical cell given by $v = (4/3) (pi) r^3$ when r is 5?

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How do you find the instantaneous rate of change for the volume of a growing spherical cell given by v = (4/3) (pi) r^3v = (4/3) (pi) r^3 when r is 5?

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How do you find the instantaneous rate of change for the volume of a growing spherical cell given by $v = (4/3) (pi) r^3$ when r is 5?