How do you find the instantaneous rate of change for $f(x)= x^3 +2x^2 + x$ for [-1,2]?

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Answer 1 · 2016-01-12T09:54:44

Instantaneous rate of change : $f' (-1) = 0$

Start from the given $f(x) = x^3+ 2x^2+x$ at $(-1, 2)$

$f' (x) = 3x^2+4x+1$

substitute $x=-1$

$f' (-1) = 3(-1)^2+4(-1)+1$

$f' (-1)= 0$

How do you find the instantaneous rate of change for f(x)= x^3 +2x^2 + xf(x)= x^3 +2x^2 + x for [-1,2]?