How do you find the instantaneous rate of change for $f(x) = x^3 + 1$ for x=1?

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Answer 1 · 2016-01-09T23:13:52

I found $3$ .

The instantenous rate of change is equal to the derivative of your function evaluated at the particular $x$ value:

$f'(x)=3x^2$

At $x=1$ :

$f'(1)=3(1)^2=3$

How do you find the instantaneous rate of change for f(x) = x^3 + 1f(x) = x^3 + 1 for x=1?