How do you find the instantaneous rate of change for #f(x) = x^2 + 3x + 4# for x=2? Calculus Derivatives Instantaneous Rate of Change at a Point 1 Answer Ratnaker Mehta Jun 14, 2016 Reqd. rate #=f'(2)=7.# Explanation: Reqd. rate #=f'(2)=[d/dx(x^2+3x+4)]_(x=2)# =#[2x+3]_(x=2)=4+3=7.# Answer link Related questions How do you find the instantaneous rate of change of a function at a point? What is Instantaneous Rate of Change at a Point? How do you estimate instantaneous rate of change at a point? How do you find the instantaneous rate of change of #f (x)= x ^2 +2 x ^4# at #x=1#? How do you find the instantaneous rate of change of #f(t)=(2t^3-3t+4)# when #t=2#? How do you find the instantaneous rate of change of #w# with respect to #z# for #w=1/z+z/2#? Can instantaneous rate of change be zero? Can instantaneous rate of change be negative? How do you find the instantaneous rate of change at a point on a graph? How does instantaneous rate of change differ from average rate of change? See all questions in Instantaneous Rate of Change at a Point Impact of this question 1255 views around the world You can reuse this answer Creative Commons License