How do you find the inflection points of #f(x)=x^5-30x^3#? Calculus Graphing with the Second Derivative Determining Points of Inflection for a Function 1 Answer anton Aug 31, 2016 0 and -3 Explanation: #df(x)=5x^4-90x^2# #d(df(x))=20x^3-180x# #20x^3-180x=0# #x=0; x=3; x=-3# #g(x)=d(d(df(x)))=60x^2-180# #g(0)=-180; g(3)=0; g(-3)=1080# 3 is not infection point. Answer link Related questions How do you find the inflection points for the function #f(x)=8x+3-2 sin(x)#? How do you find the inflection point of a cubic function? How do you find the inflection point of a logistic function? What is the inflection point of #y=xe^x#? How do you find the inflection points for the function #f(x)=x^3+x#? How do you find the inflection points for the function #f(x)=x/(x-1)#? How do you find the inflection points for the function #f(x)=x/(x^2+9)#? How do you find the inflection points for the function #f(x)=xsqrt(5-x)#? How do you find the inflection points for the function #f(x)=e^sin(x)#? How do you find the inflection points for the function #f(x)=x-ln(x)#? See all questions in Determining Points of Inflection for a Function Impact of this question 1925 views around the world You can reuse this answer Creative Commons License