How do you find the inflection points for the function f(x)=8x+3-2 sin(x)? Calculus Graphing with the Second Derivative Determining Points of Inflection for a Function 1 Answer Sonnhard May 26, 2018 Solve the equation sin(x)=0 and it must be cos(x)ne 0 Explanation: f(x)=8x+3-2sin(x) f'(x)=8-2cos(x) f''(x)=2sin(x) f'''(x)=2cos(x) Answer link Related questions How do you find the inflection point of a cubic function? How do you find the inflection point of a logistic function? What is the inflection point of y=xe^x? How do you find the inflection points for the function f(x)=x^3+x? How do you find the inflection points for the function f(x)=x/(x-1)? How do you find the inflection points for the function f(x)=x/(x^2+9)? How do you find the inflection points for the function f(x)=xsqrt(5-x)? How do you find the inflection points for the function f(x)=e^sin(x)? How do you find the inflection points for the function f(x)=x-ln(x)? How do you find the inflection points for the function f(x)=e^(3x)+e^(-2x)? See all questions in Determining Points of Inflection for a Function Impact of this question 7824 views around the world You can reuse this answer Creative Commons License