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How do you find the inflection points for the function #f(x)=8x+3-2 sinx#?

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Apr 24, 2015

#f(x)=8x+3-2 sinx#

#f'(x)=8-2 cosx#

#f''(x)= 2 sinx#

#f''(x) =2sinx = 0# at every integer multiple of #pi# and, we know the sine changes sign at every #x# intercept,

so every point:
#(n pi,0)# with integer #n# is an inflection point.

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