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How do you find the indefinite integral of #int cost/(1+sint)#?

1 Answer

Feb 8, 2017

#ln|sint + t| + C#

Explanation:

Let #u = sint + 1#. Then #du = cos t dt# and #dt = (du)/cost#.

#=>int cost/u * (du)/cost#

#=>int 1/u du#

#=>ln|u| + C#

#=>ln|sint + t| + C#

Hopefully this helps!

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