How do you find the indefinite integral of #int -(35x^(2/5))/5dx#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Alan N. Sep 23, 2016 #-5x^(7/5)+c# Explanation: #int-35x^(2/5)dx = -35/5intx^(2/5)dx# #= -35/5 {x^(7/5)/(7/5)} +c= -35/5 xx 5/7.x^(7/5)+c# #=-5x^(7/5)+c# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 1867 views around the world You can reuse this answer Creative Commons License