How do you find the important points to graph #y=f(x)=x^2+1#?

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How do you find the important points to graph #y=f(x)=x^2+1#?

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Answer 1 · 2017-03-28T18:41:58

#x^2+1# tells us something important. On the parent graph of #x^2#, the important points are #x=0#, #y=0#. The #+1# in this equation tells us that it's the same graph, except it has been shifted up one unit. So instead of #(0,0)#, now the x-intercept is #(0, 1)#. All the normal points in #x^2# have kept their #x# values, but the #y# values have increased by #1#.

We can check that in this graph.

graph{y=x^2}
graph{y=x^2+1}

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How do you find the important points to graph #y=f(x)=x^2+1#?

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