How do you find the important points to graph y=-2x-3y=2x3?

1 Answer
Nov 10, 2015

Find the points at which the line crosses the x and y axes.

Explanation:

xx intercept
When a point is on the xx axis, we know its yy value is 0. This means we can make the equation equal to 0 to find xx.

0 = -2x -30=2x3

3 = -2x3=2x (add 3 to both sides)

3/2 = -x32=x (divide by 2 on both sides)

-3/2 = x32=x (times both sides by -1)

This means x = -3/2x=32 or x = -1.5x=1.5 So our xx intercept is at the coordinate (-1.5, 0)(1.5,0)

yy intercept
On the yy axis we know the xx value is equal to 0, so we can substitute this into the equation to find the yy value.

y = -2(0) - 3y=2(0)3

y = -3y=3 (remove anything multiplied by 0)

So we now know our yy intercept is at (0,-3)(0,3)

So the important points are (-1.5, 0)(1.5,0) and (0, -3)(0,3)