How do you find the important points to graph #y = -2 sqrt(x + 2)#?

1 Answer
MeneerNask
Sep 28, 2017

Most important point is when #y=0#

Explanation:

This happens when #x=-2-> (-2,0)#

#x>=-2# otherwise the argument would become negative (not allowed).

Then you can set up a table with #x#'s chosen so that the argument becomes a square:
E,g.:
#x=-1->y=-2sqrt(-1+2)=-2->(-1,-1)#
#x=2->y=-2sqrt(2+2)=-4->(2,-4)#
#x=7->y=-2sqrt(7+2)=-6->(7,-6)#
Etc.
graph{-2sqrt(x+2) [-5.46, 14.54, -8.72, 1.28]}

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