How do you find the important points to graph g(x)=2^x-3?

1 Answer
Tony B
Oct 15, 2016

see explanation

Explanation:

Tony B

Set y=2^x - 3

At y=0"; "2^x=3

Taking logs

xlog(2)=log(3) => x=log(3)/(log(2)) ~~1.58 to 2 decimal places
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At x=0"; "y" "=" "2^0-3" " ->" "y" "=" " 1-3

y" "=" "-2
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Lim_(x->+oo)y= lim_(x->+oo)2^x-3 ->oo-3=oo

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Lim_(x->-oo) y=lim_(x->-oo)2^x-3 ->0-3=-3

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