How do you find the important points to graph #6xy = 13#?

1 Answer
Leland Adriano Alejandro
Feb 8, 2016

The graph occupies the 1st and 3rd quadrants only. The asymptotes are the x-axis and y-axis. Calculate y values using x values #+-0.25# up to #+-4#

Explanation:

Using the given #6xy=13#

use #y=13/(6x)#

when #x=+0.25# , #y=+8.66#
when #x=+0.5# , #y=+4.33#
when #x=+1# , #y=+2.166#
when #x=+2# , #y=+1.083#
when #x=+3# , #y=+0.722#
when #x=+4# , #y=+0.25#

when #x=#approaches #oo#, #y =#approaches #0# that is why #y=0# is an asymptote

at the very high + value of #y# , #x# approaches 0
also
at the very negative value of #y# , #x# approaches 0,
that is why #x=0# is also an asymptote

when #x=-0.25# , #y=-8.66#
when #x=-0.5# , #y=-4.33#
when #x=-1# , #y=-2.166#
when #x=-2# , #y=-1.083#
when #x=-3# , #y=-0.722#
when #x=-4# , #y=-0.25#

graph{y=13/(6x)[-20,20,-10,10]}

have a nice day from the Philippines

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