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How do you find the general solutions for #sin^2x=3cos^2x#?

1 Answer

Oct 7, 2015

Solve #sin^2 x = 3cos^2 x#

Ans: #pi/3 and (2pi)/3#

Explanation:

#sin^2 x = 3cos^2 x#
#tan^2x = 3#
t#an x = +- sqrt3#
a. #tan x = sqrt3# --> #x = pi/3 + kpi#
b. #tan x = -sqrt3# --> #x = (2pi)/3 + kpi#

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