How do you find the general solutions for #cos x tan x = 1/2#?

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How do you find the general solutions for #cos x tan x = 1/2#?

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Answer 1 · 2015-08-14T17:56:50

Solve: #cos x.tan x = 1/2#

Explanation:

#cos x(sin x/cos x) - 1/2 = 0#
#cos x.sin x - cos x /2 = 0#
#cos x(sin x - 1/2) = 0#

#a. cos x = 0# --> #x = pi/2# and #x = 3pi/2#
b. #sin x = 1/2# --> #x = pi/6# and #x = 5pi/6#
General answers:
#x = pi/6 + 2kpi#
#x = pi/2 + 2kpi#
#x = 3pi/2 + 2kpi#
#x = 5pi/6 + 2kpi#

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How do you find the general solutions for #cos x tan x = 1/2#?

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