How do you find the general solutions for $cos x tan x = 1/2$ ?

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How do you find the general solutions for $cos x tan x = 1/2$ ?

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Answer 1 · 2015-08-14T17:56:50

Solve: $cos x.tan x = 1/2$

Explanation:

$cos x(sin x/cos x) - 1/2 = 0$
$cos x.sin x - cos x /2 = 0$
$cos x(sin x - 1/2) = 0$

$a. cos x = 0$ --> $x = pi/2$ and $x = 3pi/2$
b. $sin x = 1/2$ --> $x = pi/6$ and $x = 5pi/6$
General answers:
$x = pi/6 + 2kpi$
$x = pi/2 + 2kpi$
$x = 3pi/2 + 2kpi$
$x = 5pi/6 + 2kpi$

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How do you find the general solutions for $cos x tan x = 1/2$ ?

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