How do you find the general solution of the differential equation #dy/dx=x^(3/2)#?

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Answer 1 · 2016-12-28T00:52:00

Solve for #dy#.

#dy = x^(3/2)dx#

Integrate both sides.

#int(dy) = int(x^(3/2))dx#

Use the rule #int(x^n)dx = (x^(n + 1))/(n + 1) + C# to solve.

#y = x^(5/2)/(5/2) + C#

#y = 2/5x^(5/2) + C#

Hopefully this helps!