How do you find the first five terms of the geometric sequence #a_1=2# r=-3?

1 Answer
Jim G.
Apr 23, 2017

#2,-6,18,-54,162#

Explanation:

#"the terms in a geometric sequence are"#

#a,ar,ar^2,ar^3,......,ar^(n-1)#

#"where r is the common ratio"#

#r=a_2/a_1=a_3/a_2= ...... =(a_n)/a_(n-1)#

To obtain a term in the sequence multiply the previous term
by r

#rArra_1=2#

#rArra_2=2xx-3=-6#

#rArra_3=-6xx-3=18#

#rArra_4=18xx-3=-54#

#rArra_5=-54xx-3=162#

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