How do you find the first and second derivative of y=e^x+e^-xy=ex+e−x?
1 Answer
Mar 2, 2017
dy/dx \ = e^x - e^(-x)
(d^2y)/(dx^2) = e^x + e^(-x)
Explanation:
Using the standard result:
d/dx e^(ax)=ae^(ax)
Then if :
y = e^x+e^(-x)
We have:
dy/dx \ = e^x - e^(-x)
And then:
(d^2y)/(dx^2) = e^x + e^(-x)
