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How do you find the exact values of the remaining five trigonometric functions of angle, given csc of the angle is -4?

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May 17, 2015

#csc x = 1/sin x = -4 -> sin x = -1/4#

#cos^2 x = 1 - sin^2 x = 1 - 1/16 = 15/16 -> cos x = +- sqrt15/4#

#tan x = - (1/4) (4/(sqrt15)) = (-sqr15)/15#

#cot x = -15/(sqrt15) = (-15sqrt15)/15 = -sqrt15 #

#sec x = 1/cos x = -4/(sqrt15)# = #-(4sqrt15)/15#

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